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Giới thiệu về bản thân

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a, có vì OM đi qua trung điểm của AB

b, vì A nằm trên đường tròn nên AO là bán kính
biết AO= 5 Vì bán kính =5

biết AB = 8 mà M là trung điểm của AB nên AM = 1/2 AB = 4
vậy áp dụng định lí pytago có AM^2 + OM^2 = AO^2
nên AO^2 - AM^2 = OM^2

hay 5^2 - 4^2 = OM^2

9 = OM^2

vậy OM = 3

b ,  Đường tròn \(\left(\right. C ; 2\) cm\(\left.\right)\) có đi qua hai điểm \(O\)  \(A\) vì đều cách nhau 2cm