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a) \(14:\frac{0,4x+0,6}{x}=7\)
\(\frac{0,4x+0,6}{x}=2\)
0,4x + 0,6 = 2.x
2x - 0,4x = 0,6
1,6x = 0,6
x = 0,375
b) \(\left(160\%+\frac{2}{3}x-x\right).12=660\)
\(\left(160\%+\frac{2}{3}x-x\right)=55\)
\(x\left(\frac{2}{3}-1\right)=53,4\)
\(-\frac{1}{3}x=\frac{267}{5}\)
\(x=\frac{267}{5}.\frac{3}{-1}\)
\(x=-160,2\)
c) \(1:\frac{1.2.3.4.....31}{2.2.2.3.2.4.....2.32}=2^x\)
\(1:\frac{1.2.3.4.....31}{2^{31}.2.3.4.....31.2^5}=2^x\)
\(1:\frac{1}{2^{36}}=2^x\)
\(2^{36}=2^x\)
\(x=36\)
\(\frac{x-1}{2018}+\frac{x-7}{503}=\frac{x-3}{1008}+\frac{x-9}{670}\)
\(\Leftrightarrow\frac{x-1}{2018}-1+\frac{x-7}{503}-4=\frac{x-3}{1008}-2+\frac{x-9}{670}-3\)
\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{2018}+\frac{1}{503}-\frac{1}{1008}-\frac{1}{670}\right)=0\)
\(\Rightarrow x=2019\)
#CBHT
Đặt A =1/2+1/4+1/8+...+1/1024
2A= 1+1/2+1/4+...+1/512
A= 1-1/1024
=>A<1hay ...
a, \(\frac{-3}{7}\)+ \(\frac{2}{9}\)= \(\frac{-13}{63}\)
b, \(\frac{-5}{11}\)+ \(\frac{6}{7}\)= \(\frac{31}{77}\)
c, \(\frac{334}{335}\)+ \(\frac{-4}{335}\)= \(\frac{66}{67}\)
\(a)\frac{36}{-84}+\frac{100}{450}=\frac{-36}{84}+\frac{100}{450}\)
Rút gọn : \(\frac{-36}{84}=\frac{-36:12}{84:12}=\frac{-3}{7}\)
\(\frac{100}{450}=\frac{100:50}{450:50}=\frac{2}{9}\)
B1 : 7 = 7
9 = 32
\(\Rightarrow MSC=BCNN(7,9)=7\cdot3^2=63\)
B2 : Thừa số phụ :
63 : 7 = 9
63 : 9 = 7
B3 : Quy đồng :
\(\frac{36}{-84}=\frac{-36}{84}=\frac{-3}{7}=\frac{-3\cdot9}{7\cdot9}=\frac{-27}{63}\)
\(\frac{100}{450}=\frac{2}{9}=\frac{2\cdot7}{9\cdot7}=\frac{14}{63}\)
\(\Rightarrow\frac{-3}{7}+\frac{2}{9}=\frac{-27}{63}+\frac{14}{63}=\frac{-27+14}{63}=\frac{-13}{63}\)
b,c, Tự làm
a, \(\frac{65}{91}+\frac{-33}{55}=\frac{5}{7}+\frac{-3}{5}=\frac{4}{35}\)
b, \(\frac{36}{-84}+\frac{100}{450}=\frac{-3}{7}+\frac{2}{9}=-\frac{13}{63}\)
c, \(\frac{-650}{1430}+\frac{588}{686}=\frac{-5}{11}+\frac{6}{7}=\frac{31}{77}\)
d, \(\frac{2004}{2010}+\frac{8}{-670}=\frac{334}{335}+\frac{-4}{335}=\frac{66}{67}\)
a) -650/1430+588/686= -5/11+ 6/7= 31/77
b) 2004/2010+8/-670= 334/335+(-4/335)=66/67
Bấm ĐÚNG cho mình nha
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}=\frac{a+b+c}{a+b+c}=1\)
\(\Rightarrow\left\{\begin{matrix}\frac{a}{b}=1\\\frac{b}{c}=1\\\frac{c}{a}=1\end{matrix}\right.\Rightarrow\left\{\begin{matrix}a=b\\b=c\\c=a\end{matrix}\right.\Rightarrow a=b=c\)
Ta có:
\(A=\frac{a^{670}b^{672}c^{673}}{a^{2015}}=\frac{a^{670}a^{672}a^{673}}{a^{2015}}=\frac{a^{2015}}{a^{2015}}=1\)
Vậy \(A=1\)
Áp dụng t/c' dãy tỉ số bằng nhau ta có:
\(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}=\frac{a+b+c}{b+c+a}=1\)
\(\Rightarrow\frac{a}{b}=1\Rightarrow a=b\) (1)
\(\Rightarrow\frac{b}{c}=1\Rightarrow b=c\) (2)
\(\Rightarrow\frac{c}{a}=1\Rightarrow c=a\) (3)
Từ (1);(2);(3) \(\Rightarrow a=b=c\)
\(\Rightarrow A=\frac{a^{670}.b^{672}.c^{673}}{a^{2015}}=\frac{a^{670}.a^{672}.a^{673}}{a^{2015}}=\frac{a^{2015}}{a^{2015}}=1\)
\(\Rightarrow A=1\)
3,14 . 4,64 + 3,14 . 5,36
= 3,14 . (4,64 + 5,36)
= 3,14 . 10
= 31,4
\(3,14 × 670 = 2103,8\)
210 380
2103,8
3,14 × 670
= 3,14 × 67 × 10
= 210,38 × 10
= 2103,8